A. 3.01 x 10²²
B. 6.02 x 10²²
C. 6.02 x10²³
D. 1.20 x 10²¹
Correct Answer: Option B
B. 6.02 x 10²²
Explanation
32g of sulphur = 6.02 x 1022 atoms 3.2g of sulphur = x ,x = \(\frac{3.2×6.02 x 1023}{32}\) = 0.602 x 1023 = 6.02 x 1022 atom
![How many molecules are there in 14 g of nitrogen at s.t.p.? [N = 14, Avogadro's constant = 6.02 x 10^23 mol-1]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "How many molecules are there in 14 g of nitrogen at s.t.p.? [N = 14, Avogadro's constant = 6.02 x 10^23 mol-1]")
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