The mass of silver deposited when a current of 10A is passed through a solution of silver salt for 4830s is? [Ag = 108, F = 96500 c mol-1]

A. 108.0g
B. 54.0g
C. 27.0g
D. 13.5g

Correct Answer:

Option B – 54.0g

Explanation

Ag + e → Ag+
If w 96500 C deposit 108g of silver
∴ 10 * 4830 will deposit (10 * 4830 * 108)/96500
= 5216400/96500 = 54.06g