A. 48.0°C
B. 38.0°C
C. 28.3°C
D. 23.0°C
Correct Answer:
Option C = 28.3°C
Explanation
GIVEN DATA:
where ΔL is the increase in length = 0.01
L1 is the initial length = 100
T1 = 20
T2 = ?
α is the linear expansivity of iron = 1.2 x 10−5−5°C
Formula
ΔL = L1αΔT
ΔT = ΔL/L1α
ΔT is the change in temperature = T2 – T1
T2 = ΔL/L1α
+ T1
T2 = 0.01/100×1.2×10−5 + 20
T2 = 8.3 + 20
T2 = 28.3
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