A. 4-methylpent-1-ene
B. 3-methylpent-2-ene
C. 2-methylpent-1ene
D. 2-methylpent-4-ene
Correct Answer:
Option A – 4-methylpent-1-ene
The IUPAC nomenclature for the compound above is?
![Analysis of a hydrocarbon shows that it contains 0.93g of Carbon per gram of the compound. The mole ratio of carbon to hydrogen in the compound is [H = 1.0, C=12.0]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Analysis of a hydrocarbon shows that it contains 0.93g of Carbon per gram of the compound. The mole ratio of carbon to hydrogen in the compound is [H = 1.0, C=12.0]")
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