by Sunday | Nov 11 | Physics JAMB
A. 100Ω B. 200Ω C. 300Ω D. 500Ω Correct Answer: Option B = 200Ω Explanation Power of the lamp = 60W; I=P/V I=60/120 = 0.5A R=V/I Rmains = 220/0.5 = 440Ω Rlamp = 120/0.5 = 240Ω ∴ The non-inductive resistance to keep the lamp = (440−240)Ω =...
by Sunday | Nov 11 | Physics JAMB
A. 3 x 10-5 B. 3 x 10-6 C. 5 x 10-5 D. 5 x 10-5 Correct Answer: Option D = 5 x 10-5 Explanation Since the wires are parallel to each other, the forces which they exert on each other are equal and opposite, since they must agree with newton’s law of action and...
by Sunday | Nov 11 | Physics JAMB
A. electric charge B. electric current C. Energy D. Momentum Correct Answer: Option C = Energy Explanation Lenz’s law of electrical magnetic induction is usefully referred to as the law of conservation of...
by Sunday | Nov 11 | Physics JAMB
A. A current balance B. a moving coil ammeter C. a moving iron ammeter D. an inverter Correct Answer: Option C = a moving iron ammeter
by Sunday | Nov 11 | Physics JAMB
A. 4.0 x 10²W B. 5.0 x 10²W C. 4.0 x 10³W D. 5.0 x 10³W Correct Answer: Option D – 5.0 x 10³W Explanation In general, Power = IV; ⟹ 40KW = IV; Therefore 40000 = 1×800⟹I=40000/800=50A, tune the current through Resistor = 50A power loss= I²R = 50² x 2 = 2500 x 2 =...