by Sunday | Nov 12 | Physics JAMB
A. 1.05 x 103s B. 1.05 x 105s C. 1.05 x 102s D. 1.05 x 104s Correct Answer: Option A = 1.05 x 103s Explanation Power of heater = lvt = 2 x 240 x t heat required to boil the water = Mct = 2.5 x 4.2 x 103 x (100.52) = 2.5 x 4. 2 x 103 x 48 2 x 240 x t = 2.5 x 4.2 x 103...
by Sunday | Nov 12 | Physics JAMB
A. change in volume B. differential expanssion C. change in pressure D. change in length Correct Answer: Option C = change in pressure Explanation The thermometric property of a constant volume thermometer is change in pressure with...
by Sunday | Nov 12 | Physics JAMB
A. 8.00 x 10-3 m3 B. 1.25 x 10-4 m3 C. 1.92 x 10-4 m3 D. 4.61 x 10-3 m3 Correct Answer: Option B = 1.25 x 10-4 m3 Explanation R.D = (density of the subs)/density of water 19.2 =(P)/103; ∴P = 19.2 X 103 But Vol. = (Mass)/density = (2.4)/19.2 x 103 = 1.25 x...
by Sunday | Nov 12 | Physics JAMB
A. damp and rough B. damp and smooth C. dry and rough D. dry and smooth Correct Answer: Option C = dry and rough
by Sunday | Nov 12 | Physics JAMB
A. the cube will melt after a period of time B. the cube will float C. the cube will sink in water D. the cube will rest at an equilibrium position in water Correct Answer: Option B – the cube will float Explanation For the uniform cube 10cm volume = 10 x 10 x...