A body of mass 2kg is suspended from the ceiling of a lift with a light inextensible string. lf the lift moves upwards with acceleration of 2ms−². Calculate the magnitude of the tension in the string (g = 10ms−²)
A. 24N B. 20N C. 16N D. 4N E. 0N Correct Answer: Option C – 16N Explanation T + ma = mg T = mg – ma = 2 x 10 – 2 x 2 = 16N
A body of mass 4.2kg moving with velocity 10ms−¹ due east, hits a stationary body of mass 2.8kg. If they stick together after collision and move with velocity V due east, calculate the value of V
A. 3ms−¹ B. 6ms−¹ C. 7ms−¹ D. 15ms−¹ E. 17ms−¹ Correct Answer: Option B – 6ms−¹ Explanation M1U = (M1 + M2)V = 4.2 x 10 = (4.2 = 2.8)V ∴ V = 4.2 x 10/7.0 = 6m/s
The magnitude of the force required to make an object of mass M move with speed V in a circular path of radius R is given by the expression.
A. mr/v B. (mr)²/v C. mv²/r D. mv/r² E. mv/r Correct Answer: Option C – mv²/r
Two spanners X and Y of lengths 15cm and 20cm respectively are used in turn to give a screw of pitch 2mm one complete rotation. If Rx and Ry are the respective velocity ratios of the spanners then the ratio Rx : Ry is
A. 1:50 B. 3:20 C. 3:4 D. 4:3 E. 20:3 Correct Answer: Option C – 3:4 Explanation Rx = 15/0.2 = 75 Ry = 20/0.2 = 100 Rx : Ry = 75 : 100 = 3 : 4Products
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