by Sunday | Nov 15 | Physics JAMB
A. 1Ω B. 2Ω C. 3Ω D. 4Ω Correct Answer: Option C = 3Ω Explanation I = V/R = 0.6E/3 = 0.2E Again, I = E / (R+ϒ) = E / (3+ϒ) Divide eqn (2) by eqn (1) I/I = E / (3+ϒ) x I / 0.2E => 0.2(3+ϒ) = 1 0.6 x 0.2ϒ = 1 ∴0.2ϒ = -0.6 => ϒ = 0.6 / 0.2 = 3Ω ϒ =...
by Sunday | Nov 15 | Physics JAMB
A. x -rays B. ultraviolet rays C. infrared rays D. gamma rays Correct Answer: Option B – ultraviolet rays
by Sunday | Nov 15 | Physics JAMB
A. 51.9Ω B. 52.9Ω C. 55.9Ω D. 57.6Ω Correct Answer: Option B = 52.9Ω Explanation Electric Power = IV = I2R = V2/R thus for a device rated 1000 W, 230V, from the relation P = V2/R, 1000 = (230)2/R => R = (230)2/1000 = 52900/1000 =...
by Sunday | Nov 15 | Physics JAMB
A. cornea B. iris C. retina D. optic nerve Correct Answer: Option B – iris Explanation The iris controls the amount of light by limiting the volume of light admitted. The lens then focuses the light onto the retina, forming an inverted image. The lens changes...
by Sunday | Nov 15 | Physics JAMB
A. 2 A B. 3 A C. 4 A D. 5 A Correct Answer: Option C = 4 A Explanation 1 KW = 1000 watts, power P = IV, thus for a mains of 250 V, the maximum permissible Current I = 1/V = 1000/250 = 4 A Thus the fuse rating in the plug should be 4...
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