by Sunday | Nov 10 | Physics JAMB
A. 0.625 J B. 6.250 J C. 62.500 J D. 625.000 J Correct Answer: Option A – 0.625 J Explanation Energy stored in a spring = ½Ke² = ½ x 500(0.05)² = 0.625J
by Sunday | Nov 10 | Physics JAMB
A. 25.00 B. 2.50 C. 0.50 D. 0.25 Correct Answer: Option D – 0.25 Explanation F = (mv²)/r = (100 x 5²)/10 = 2500/10 = 250 R = mg = 100 x 10 = 1000N coefficient of friction, µ = (F)/R = (250)/1000 =...
by Sunday | Nov 10 | Physics JAMB
A. diffusion B. cohesion C. adhesion D. viscosity Correct Answer: Option C – adhesion Explanation since currency and finger contain unlike molecules, the force involved is adhesion
by Sunday | Nov 10 | Physics JAMB
A. h =(u)²/g B. h = (u)²/4g C. h = (2u)²/g D. h = (u)²/2g Correct Answer: Option B – h = (u)²/4g Explanation From V² = U² + 2as O = U² – 2gH, since at maximum height H, the final velocity, v = O. ∴ H = (U)²/2g PE = KE at (1)/2 H = (U)²/2g x (1)/2 =...
by Sunday | Nov 10 | Physics JAMB
A. 0.200m B. 8.000m C. 0.125m D. 2.100m E. No Correct Option Correct Answer: Option E = No Correct Option Explanation The person’s image distance v will be at the distance of 0.1m = 10cm for him to see objects at a distance of u.F = 5.0cm 1/v+1/u=1/f ⟹...
by Sunday | Nov 10 | Physics JAMB
A. 3.0 x 1014 Hz B. 6.0 x 1014 Hz C. 6.0 x 1012 Hz D. 2.5 x 1014 Hz Correct Answer: Option B – 6.0 x 1014 Hz Explanation f = c/λ ∴ f = c/λ = 3 x 108λ / 500 x 109 =6.0 x 1014 Hz