by Sunday | Nov 12 | Physics JAMB
A. 2.56 x 106N B. 2.50 x 106N C. 2.80 x 103N D. 2.50 x 103N Correct Answer: Option D – 2.50 x 103N Explanation In terms of dimension: power , P, = ML2T3 Force F1 = MLT-2; Vel, V, LT-1 From the above, => P = F x V i.e, ML2T-3 = MLT-2 x LT-1 ML2T-3 => 80,000...
by Sunday | Nov 12 | Physics JAMB
A. 100N B. 1500N C. 250N D. 150N Correct Answer: Option D – 150N Explanation For vertical equilibrium, we have 2Ty = 75N But Ty/T = adj/hyp = cos 60° ∴ Ty = T Cos 60° => 2Ty = 2Tcos 60o = 75N 2 x T x 0.5 = 75 => T = 75N ∴ Total tension in the rope = 2T. =...
by Sunday | Nov 12 | Physics JAMB
A. 1/32 B. 1/16 C. 1/ 8 D. 1/4 Correct Answer: Option B – 1/16 Explanation 80 days = 4 half-life (i.e 4 x 20 days = 80 days) But the fraction always left by any radioactive material after 4half lives is (1/2)4 =...
by Sunday | Nov 12 | Physics JAMB
A. 100 Ω B. 200 Ω C. 300 Ω D. 500 Ω Correct Answer: Option B – 200 Ω Explanation Power of the lamp = 60W = (V²)/R and the voltage rate = 120v. R = (V²)/60 = (120 X 120)/60 = 240 Ω, the fuse wire that should ensure current does not exceed this value should be...
by Sunday | Nov 12 | Physics JAMB
A. a current balance B. a moving current ammeter C. a moving iron ammeter D. an inverter Correct Answer: Option C – a moving iron ammeter
by Sunday | Nov 12 | Physics JAMB
A. 4.0 x 102W B. 5.0 x 102W C. 4.0 x 103W D. 5.0 x 103W Correct Answer: Option D – 5.0 x 103W Explanation In general, power = IV; 40kw = IV. ∴ 40,000 = 1 x 800 1 = (40.000)/800 = 50A. tune the current through resistor = 50A. ∴ power loss = 12R = 502 X 2 = 2500 X...