In the calibration of an ammeter using faraday’s laws of electrolysis, the ammeter reading is kept constant at 1.2A. If 0.990g of copper is deposited in 40 minutes; the correction to be applied to the ammeter is

A bead traveling on a straight wire is brought to rest at 0.2m by friction. If the mass of the bead is 0.01kg and the coefficient of friction between the bead and the wire is 0.1 determine the work done by the friction?

A. 2×10‾3J B. 2×10‾3J C. 2×101J D. 2×102J Correct Answer: Option B Explanation Work done by friction = Friction force x Displacement from the relation, f = uR where u = coefficient of friction; R= Normal reaction F = u mg (R =mg) = 0.1 x 0.01 x 10 work done = F x...

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