An engineer intends to deviate a light ray from its path by 120° through reflection from a plane mirror. Calculate the angle of incidence?
A. 60° B. 40° C. 30° D. 20° Correct Answer: Option C – 30° Explanation Angle of deviation = 180 – [i + v] = 180 – 2i [since i = v] ∴ 120 = 180 – 2i 2i = 180 – 120 = 60 ∴ i =...
A transverse wave is applied to a string whose mass per unit length is 3 x 10−²kgm−¹. If the string is under a tension 12N; the speed of the propagation of the wave is?
A. 5 ms−¹ B. 20 ms−¹ C. 30 ms−¹ D. 40 ms−¹ Correct Answer: Option B = 20 ms−¹
A travelling wave moving from left to right has an amplitude of 0.15m; a frequency of 550Hz and a wavelength of 0.01m. The equation describing the wave is?
A. y = 0.15 sin 200π(x – 5.5t) B. y = 0.15 sin π(0.01x – 5.5t) C. y = 0.15 sin 5.5π(x – 200t) D. y = 0.15 sin π(550x – 0.01t) Correct Answer: Option A – y = 0.15 sin 200π(x – 5.5t) Explanation The general wave equation is given by Y...The velocity y of a particle in a time t is given by the equation. y = 10 + 2t². Find the instantaneous acceleration after 5 seconds?
A. 60 ms−² B. 20 ms−² C. 15 ms−² D. 10 ms−² Correct Answer: Option B – 20 ms−² Explanation The velocity V = 10 + 2t² But acceleration, a = dv/dt thus if V = 10 + 2t² dv/dt = 4t And t = 5s then a = 4×5 = 20m/s² ∴a =...
Light of energy 5eV falls on a metal of work function 3eV and electrons are liberated. The stopping potential is?
A. 1.7V B. 2.0V C. 8.0V D. 15.0V Correct Answer: Option B – 2.0V Explanation For a photoemitted electron, eV = K.E.max, where V = stopping potential and K.E. = maximum kinetic energy of the photo emitted electron given by K.E. = Energy of incident rad –...Products
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