Warning: preg_match_all(): Compilation failed: missing terminating ] for character class at offset 113 in /home/erudites/web/erudites.ng/public_html/wp-content/plugins/seo-by-rank-math/includes/replace-variables/class-post-variables.php on line 543

Warning: preg_match_all(): Compilation failed: missing terminating ] for character class at offset 113 in /home/erudites/web/erudites.ng/public_html/wp-content/plugins/seo-by-rank-math/includes/replace-variables/class-post-variables.php on line 543
One Mole Of A Compound M(HCO3)2 Has A Mass Of 162g. Calculate The Relative Atomic Mass Of M. [H = 1, C =12, O = 16] - Erudites Academy
Warning: preg_match_all(): Compilation failed: missing terminating ] for character class at offset 113 in /home/erudites/web/erudites.ng/public_html/wp-content/plugins/seo-by-rank-math/includes/replace-variables/class-post-variables.php on line 543

A. 122
B. 101
C. 53
D. 40

Correct Answer:

Option D – 40

Explanation

One of the mole of M(HCO3)2 = 162g; M +(1 + 12 + 16 x 3) x 2 = 162; M +122 = 162,:. M = 162 – 122 = 40g

Copyright warnings! Do not copy.