A. 4H+ + 4e− → 2H2
B. 4OH− + 4e− → 2H2O + O2
C. 2OH− + 2e− → 2OH
D. 2OH− + 2OH− → 2H2O + O2
Correct Answer:
Option B = 4OH− + 4e− → 2H2O + O2
In the electrolysis of CuSO4(g) using platinum electrodes; the reaction at the anode is?
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