In a nuclear fission process, the mass defect was 1.2 x 10^‾5 kg. Calculate the energy released. [speed of the light in vacuum = c = 3.0 x 10^8ms‾¹]

by | Jan 25 | Physics WAEC | 0 comments

A. 1.08 x 10^11J
B. 5.20 x 10^11J
C. 1.08 x 10^12J
D. 2.50 x 10^13J

Correct Answer: Option C

C. 1.08 x 10^12J

Explanation

using the formula:

E = Mec²

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