A. 1/4 of its former value
B. 1/16 of its former value
C. 1/2 of its former value
D. 4 times its former value
Correct Answer:
Option B – 1/16 of its former value
Explanation
For the two-point charges, the magnitude of the electrostatic force between them is given by the equation:
F ∝ 1/r2, and if the distance is increased by a factor of 4, that is new distance = 4r,
then, new force F ∝ 1/(4r)2
= ∝ 1/16r2
Thus it will be 1/16 of the former value
then, new force F ∝ 1/(4r)2
= ∝ 1/16r2
Thus it will be 1/16 of the former value

![Two spheres of masses 100kg and 90kg respectively have their centres separated by a distance of 1.0m. Calculate the magnitude of the force of attraction between them. [G = 6.70 x 10‾¹¹Nm‾²kg‾²] Two spheres of masses 100kg and 90kg respectively have their centres separated by a distance of 1.0m. Calculate the magnitude of the force of attraction between them. [G = 6.70 x 10‾¹¹Nm‾²kg‾²]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png)