Solution
1000cm³ of solution contain 6.44 m of salt
Therefore 100 cm³ of solution contains
(6.44/1000 x 100) = 0.644 mole of salts
Molar mass of KNO3 = 39 + 14 + (16 x 3) = 101 g/mole
Therefore Mass of salt = 0.644 x 101 = 65 . 044
= 65.0g
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![Calculate the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm‾³ solution. [NaOH = 40 g mol‾¹]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Calculate the mass of sodium hydroxide in 5.00 dm³ of a 0.125 mol dm‾³ solution. [NaOH = 40 g mol‾¹]")