A. 0.75 J
B. 7.50 J
C. 75.00 J
D. 750.00 J
Correct Answer:
Option A – 0.75 J
Explanation
Energy stored in a stretched wire (strain energy)
= average force x extension
= ½Fe
= ½ x 300N (30.5 – 30.0) x 10-2 m
= 150 x 0.5 x 10-2 = 0.75J
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