A. 2 sec
B. 3 sec
C. 4sec
D. 3.2sec
Correct Answer:
Option D – 3.2sec
Explanation
From S = ut + ½gt²
u = 0ms-1
50 = (0 × t) + ½(10)(t²)
50 = 5.0t²
t² =50/5
t = √10
t = 3.2sec
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![A body of mass 1000kg is released from a height of 10m above the ground. Determine its kinetic energy just before it strikes the ground. [g = 10ms‾²]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A body of mass 1000kg is released from a height of 10m above the ground. Determine its kinetic energy just before it strikes the ground. [g = 10ms‾²]")
