If a body mass 5kg is thrown vertically upwards with velocity U; at what height will the potential energy equal to the kinetic energy?

A. h =(u)²/g
B. h = (u)²/4g
C. h = (2u)²/g
D. h = (u)²/2g

Correct Answer:

Option B – h = (u)²/4g

Explanation

From V² = U² + 2as
O = U² – 2gH, since at maximum height H, the final velocity, v = O.
∴ H = (U)²/2g

PE = KE at (1)/2 H = (U)²/2g x (1)/2 = U²/4g