A. 0.004 mol dm‾³
B. 0.020 mol dm‾³
C. 0.200 mol dm‾³
D. 0.400 mol dm‾³
Correct Answer:
Option A = 0.004 mol dm‾³
Explanation
M1V1 =M2V2
M1 = initial molarity
V1 = initial volume in liters
M2 = final molarity
V2 = final volume in liters
0.200 X 5.00 = M2 X 250
M2 = 1/250
M2 = 0.004 moldm-3
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![Consider the reaction represented by the equation: 2NaHCO3 → Na2CO3 + H2O + CO2. What is the mass of sodium trioxocarbonate (lV) produced by the complete decomposition of 33.6 g of sodium hydrogen trioxocarbonate (IV)? [NaHCO3 = 84, Na2CO3 = 106]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Consider the reaction represented by the equation: 2NaHCO3 → Na2CO3 + H2O + CO2. What is the mass of sodium trioxocarbonate (lV) produced by the complete decomposition of 33.6 g of sodium hydrogen trioxocarbonate (IV)? [NaHCO3 = 84, Na2CO3 = 106]")
