A. 2400J
B. 6800J
C. 7251J
D. 24000J
Correct Answer: Option D
D. 24000J
Explanation
The quantity of heat needed to melt ice = mL (where m is the mass of ice and L is the specific latent heat of fusion of ice)
Q = 50×336=16800J but this is 70% of the total heat supplied so that we have,
70% total heat = 16800J
70/100 heat=16800J
Total heat supplied = 16800×10070=24000J
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![Ice of mass 10g at 5ºC was completely converted to water at 0ºC, calculate the quantity of heat used. [specific heat capacity of ice = 2.1 Jg-1K-1, specific latent heat of fusion of ice = 336 Jg‾¹]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Ice of mass 10g at 5ºC was completely converted to water at 0ºC, calculate the quantity of heat used. [specific heat capacity of ice = 2.1 Jg-1K-1, specific latent heat of fusion of ice = 336 Jg‾¹]")
