Ice of mass 50g at 0°C was completely melted by 70% of the total heat energy supplied. Calculate the total heat energy supplied [Specific latent heat of fusion of ice = 336Jg−1]

A. 2400J
B. 6800J
C. 7251J
D. 24000J

Correct Answer: Option D

D. 24000J

Explanation

The quantity of heat needed to melt ice = mL (where m is the mass of ice and L is the specific latent heat of fusion of ice)

Q = 50×336=16800J but this is 70% of the total heat supplied so that we have,

70% total heat = 16800J

70/100 heat=16800J

Total heat supplied = 16800×10070=24000J