A. 2400J
B. 6800J
C. 7251J
D. 24000J
Correct Answer: Option D
D. 24000J
Explanation
The quantity of heat needed to melt ice = mL (where m is the mass of ice and L is the specific latent heat of fusion of ice)
Q = 50×336=16800J but this is 70% of the total heat supplied so that we have,
70% total heat = 16800J
70/100 heat=16800J
Total heat supplied = 16800×10070=24000J
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![A solid of mass 0.5kg initially at 50oC melts at 60oC. Calculate the quantity of heat required to melt it completely. [specific heat capacity of the solid =2.0KJ kg-1K-1][Specific latent heat of fusion of solid =1.0 KJ kg-1]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A solid of mass 0.5kg initially at 50oC melts at 60oC. Calculate the quantity of heat required to melt it completely. [specific heat capacity of the solid =2.0KJ kg-1K-1][Specific latent heat of fusion of solid =1.0 KJ kg-1]")
