How many moles of sodium trioxocarbonate (IV) are there in a 25 cm³ solution which required 10cm³ of 0.05 mol dm-³ hydrochloric acid solution to neutralize it?

by | Oct 14 | Chemistry JAMB | 0 comments

Na2CO3(g) + 2HCl(aq) → 2NaCl(aq) + H2O(l) + CO2(g)

A. 1.000 mole
B. 0.100 mole
C. 0.010 mole`
D. 0.111 mole

Correct Answer:

Option C = 0.100 mole

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