A. 3.01 x 1020
B. 3.01 x 1027
C. 6.02 x 1019
D. 6.02 x 1027
Correct Answer:
Option C = 6.02 x 1019
How many molecules of oxygen would occupy a volume of 2.24 cm³ at s.t.p? [Molar volume at s.t.p = 22,400 cm³, Avogadro’s number = 6.02 x 10²³]
![The number of sulphur atoms in 3.20g of SO2(g) is [O = 16.0;S = 32.0; Avogadro constant = 6.02 X 10²³]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "The number of sulphur atoms in 3.20g of SO2(g) is [O = 16.0;S = 32.0; Avogadro constant = 6.02 X 10²³]")
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