How long would it take to deposit 0.08g of copper from CuCl2 solution by passing a current of 0.5A? [Cu = 64, F = 96500 C mol-1]

A. 6 mins
B. 8 mins
C. 24 mins
D. 48 mins

Correct Answer:

Option B – 8 mins

Explanation

Cu²+ + 2e → Cu(s)
2 X 96500C deposit 64g of Cu
∴ x quantity of electricity wil deposit 0.08
x = (2 * 96500 * 0.08)/64 =241.25 coulomb.
Q = It
241.25 = 0.5t
t = 241.25/60 = 8 mins