A. -46KJ mol -1
B. -184KJmol -1
C. -92KJmol -1
D. 184KJmol -1
E. +46KJmol -1

Correct Answer:

Option A – -46KJ mol -1

Explanation

In the reaction, the enthalpy of formation 2 mole of NH3 is – 92kJ. Therefore the standard ΔH of formation = −92kJ/2 =−46KJmol−1.

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