Consider the following reaction equation: CaCO3(s) + 2HCI(aq) → CaCl2(aq) + H2O(l) + CO2(g). What mass of CaCI2 would be obtained when 25.0g of CaCO3(s) is reacted with excess HCI(aq)? [CaCO3 = 100; CaCI2 = 111]

by | May 8 | Chemistry WAEC | 0 comments

A. 4.00g
B. 4.44 g
C. 18.9 g
D. 27.8 g

Correct Answer: Option D

D. 27.8 g

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