by Sunday | Sep 15 | Chemistry JAMB
A. NH3—C—C=O B. CHO C. CO D. CNH2 Correct Answer: Option A – NH3—C—C=O Explanation Xanthopreitic test for the presence of protein, when conc nitric acid is added to the drop, an intense yellow colouration is observed. It contains all the functional group of...
by Sunday | Sep 15 | Chemistry JAMB
A. 2–ethyl butane B. butane C. 2–methyl butane D. 2–methyl propane Correct Answer: Option C = 2–methyl butane Explanation C5H12 has 5 carbons acid 12 hydrogens. 2–methyl butane No of carbon=5 No of hydrogen=12...
by Sunday | Sep 15 | Chemistry JAMB
A. +7 B. +3 C. +5 D. +6 Correct Answer: Option C = +5 Explanation If the rules are followed, it is non-negotiable that +5 is the suitable answer to the question.
by Sunday | Sep 15 | Chemistry JAMB
A. 400k B. 480k C. 550k D. 600k Correct Answer: Option D – 600k Explanation At constant pressure connotes Charle’s law V1T1 = V2T2 2dm³/300k = 2 x (2dm³/T2) T2= 600k
by Sunday | Sep 15 | Chemistry JAMB
A. Low melting point B. Weak electropositive character C. High boiling point D. White lustrous appearance Correct Answer: Option A – Low melting point Explanation Tin has a melting point of 232° which enables it to be unaffected by air at ordinary temperature...
by Sunday | Sep 15 | Chemistry JAMB
A. 54.0g B. 27.0g C. 13.5g D. 108.0g Correct Answer: Option A – 54.0g Explanation Recall that mass deposited = MmIt/96500n Mm =108, t = 4830s I = 10A, n = 1 m = 108 × 10 × (4830/96500) × 1 m =...