![Calculate the amount in moles of a gas which occupies 10.5 dm³ at 6 atm and 30°C [R = 082 atmdm³k-¹ mol]](https://erudites.ng/wp-content/uploads/2020/06/past-questions-and-answers.jpg)
by Sunday | Sep 15 | Chemistry JAMB
A. 2.536 B. 1.623 C. 4.736 D. 0.394 Correct Answer: Option A – 2.536 Explanation For an ideal gas PV = nRT Amount in moles = n Volume v = 10.5dm³ Pressure P = 6atm Temperature T = 30°C + 273 = 303k R, Gas constant = 0.082 atmdm³k-¹ mol Recall from ideal gas...
by Sunday | Sep 15 | Chemistry JAMB
A. Reforming B. Polymerization C. Distillation D. Cracking Correct Answer: Option D – Cracking Explanation Ethene is produced from cracking which involves breaking up large hydrocarbon molecules into smaller and more useful bits. This is achieved by using high...
by Sunday | Sep 15 | Chemistry JAMB
A. positive ion B. neutral atom of a metal C. neutral atom of a non-metal D. negative ion Correct Answer: Option D – negative ion Explanation protons = 9 neutrons = 10 electrons = 10 Electronic configuration = 2, 8 Ground state Electronic configuration=2, 7 It...
by Sunday | Sep 15 | Chemistry JAMB
A. further heating B. adding concentrated H2SO4 C. cooling the acid solution with cold water D. bubbling air through the acid solution Correct Answer: Option D – bubbling air through the acid solution Explanation Bubbling of air through the acid solution removes...
by Sunday | Sep 15 | Chemistry JAMB
A. 20 B. 32 C. 14 D. 12 Correct Answer: Option B – 32 Explanation Molecular mass = vapour density x 2 Mm of XO2 = x + 16(2) = x + 32 vapour density = 32 ∴ x + 32 = 32 × 2 x + 32 = 64 x = 64 – 32 x = 32 ∴ the relative molecular mass of X is 32 Relative...
by Sunday | Sep 15 | Chemistry JAMB
A. −100°C B. −273°C C. −373°C D. 0°C Correct Answer: Option B = −273°C Explanation Where −273°C = 0 K i.e −273°C + 273 = 0 K At zero kelvin, the volume of a gas becomes zero.
Land Law and the Consequences of Unauthorized Land Transfers in Nigeria
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