Calculate the mass of ice that would melt when 2kg of copper is quickly transferred from boiling water to a block of ice without heat loss?

Specific heat capacity of copper = 400JKg-1K-1
Latent heat of fusion of ice = 3.3 x 105JKg-1

A. 8/33kg
B. 33/80kg
C. 80/33kg
D. 33/8kg

Correct Answer:

Option A – 8/33kg

Explanation

Heat given off by the copper = MCt
= 2 x 400 x (100 – 0)
Heat absorbed by the ice = ML
= M x 3.3 x 105
Heat lost = Heat gained
∴ M x 3.3 x 105 = 2 x 400 x 100
∴ M = (2 x 400 x 100)/3.3 x 105
= 8/33Kg