A waterfall is 1.260m high. Calculate the change in temperature of a quantity of water that falls from the top to the bottom of the waterfall. (Neglect heat losses to the surroundings, take g as 10m−² and specific heat capacity of water as 4200Jkg−¹K−¹)
A. 0.3°C
B. 3.0°C
C. 33.3°C
D. 42.0°C
E. 100.0°C
Correct Answer:
Option B – 3.0°C
Explanation
Δt=gh/c=(1260×10)/4200
= 3.0°
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![Water falls through a height of 50m. Determine the temperature rise at the bottom of the fall. [Neglect energy losses. Specific heat capacity of water = 4200Jkg-1 K-1, g = 10m/s²]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Water falls through a height of 50m. Determine the temperature rise at the bottom of the fall. [Neglect energy losses. Specific heat capacity of water = 4200Jkg-1 K-1, g = 10m/s²]")