A. C3H8O
B. C6H12O
C. C6H12O2
D. C12H12O11
Correct Answer:
Option B – C6H12O
Explanation
C = 72 / 12 H = 12 / 1 O = 16 / 16
C = 6 H = 12 O = 1
: EMPIRICAL FORMULA
C6H12O
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![A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen. If the molar mass of the compound is 180. Find the molecular formula. [H = 1, C = 12, O = 16]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A compound contains 40.0% carbon, 6.7% hydrogen and 53.3% oxygen. If the molar mass of the compound is 180. Find the molecular formula. [H = 1, C = 12, O = 16]")