An object weighs 60.0N in air, 48.2N in a certain liquid X, and 44.9N in water, Calculate the relative density of X.

by Sunday | May 21 | Physics WAEC | 0 comments

A. 3.300
B. 1.279
C. 0.932
D. 0.782

Correct Answer: Option D

D. 0.782

Explanation

R.d = Wt in Air-Wt in Air-Wt in water

= (60.0−48.2)/(60.0−44.9)

= 0.782

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