An immersion heater rated 400W, 220V is used to heat a liquid of mass 0.5kg. If the temperature of the liquid increases uniformly at the rate of 2.5ºC per second, calculate the specific heat capacity of the liquid. [Assume no heat is lost]

by | May 21 | Physics WAEC | 0 comments

A. 1100Jkg-1K-1
B. 320Jkg-1K-1
C. 200Jkg-1K-1
D. 176Jkg-1K-1

Correct Answer: Option B

Explanation

pt = mcθ

C = pt/mθ

= (400×1)/(0.5×2.5)

= 320Jkg-1K-1

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