An elastic string of force constant 200N m-1 is stretched through 0.8m within its elastic limit. Calculate the energy stored in the string.

by | May 21 | Physics WAEC | 0 comments

A. 64.0J
B. 80.0J
C. 128.0J
D. 160.0J

Correct Answer: Option A

A. 64.0J

Explanation

E = ½Ke²

= ½×200(0.8)²

=64J

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