An ammeter connected to an a.c circuit records 5.5. The peak current in the circuit is? by Sunday | May 19 | Physics WAEC | 0 comments A. 7.8A B. 7.1A C. 3.8A D. 3.5A Correct Answer: Option A A. 7.8A Explanation Io=Irms×√2 =5.5×1.41=7.8A Users Also Read These:A cell of e.m.f. 1.5V and internal resistance of…A cell of e.m.f. 1.5 V and internal resistance of…In an A.C circuit, the ratio of r.m.s value to peak…A cell of e.m.f 1.5V and internal resistance 2.552…In the diagram below, three identical lamps each of…