A. 0.11kg
B. 0.12kg
C. 0.13kg
D. 0.14kg
Correct Answer:
Option A – 0.11kg
Explanation
Heat capacity (o) = mass (kg) specific heat of a substance (C2)
i.e Q = MC
where Q = 40 J/L, m = ?(380 J/Kgk)
40 = m × 380
m = 0.11kg (Approx)
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![An immersion heater rated 400W, 220V is used to heat a liquid of mass 0.5kg. If the temperature of the liquid increases uniformly at the rate of 2.5ºC per second, calculate the specific heat capacity of the liquid. [Assume no heat is lost]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "An immersion heater rated 400W, 220V is used to heat a liquid of mass 0.5kg. If the temperature of the liquid increases uniformly at the rate of 2.5ºC per second, calculate the specific heat capacity of the liquid. [Assume no heat is lost]")
