A tuning fork of frequency 600Hz is sounded over a closed resonance tube. If the first and second resonant positions are 0.130m and 0.413m respectively, calculate the speed of sound in air.

by | May 23 | Physics WAEC | 0 comments

A. 508.4ms‾¹
B. 480.0ms‾¹
C. 339.6ms‾¹
D. 169.8ms‾¹

Correct Answer: Option C

C. 339.6ms‾¹

Explanation

v=fλ

v=2f×(l2−l1)

v=2×600×(0.413−0.130)

v=1200×0.283

v=339.6ms‾¹

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