Deprecated: Return type of AdvancedAds\Abstracts\Data::offsetGet($offset) should either be compatible with ArrayAccess::offsetGet(mixed $offset): mixed, or the #[\ReturnTypeWillChange] attribute should be used to temporarily suppress the notice in /home/erudites/web/erudites.ng/public_html/wp-content/plugins/advanced-ads/includes/abstracts/abstract-data.php on line 431
A Parallel Plate Capacitor Of Capacitance 600μF Has A Potential Difference Of 200V Between Its Plates. Calculate The Charge On Either Plate Of The Capacitor. - Erudites Academy

A parallel plate capacitor of capacitance 600μF has a potential difference of 200V between its plates. Calculate the charge on either plate of the capacitor.

by | May 21 | Physics WAEC | 0 comments

A. 1.2C
B. 3.3C
C. 3330.0C
D. 12.0000.0C

Correct Answer: Option A

A. 1.2C

Explanation

Q = CV

= 600 x 10-6 x 200 = 1.2C

Users Also Read These:

Copyright warnings! Do not copy.

Earn Your Degree In 3 Years Without Writing UTME. Click Here To Learn More.