A parallel plate capacitor of capacitance 600μF has a potential difference of 200V between its plates. Calculate the charge on either plate of the capacitor.

by | May 21 | Physics WAEC | 0 comments

A. 1.2C
B. 3.3C
C. 3330.0C
D. 12.0000.0C

Correct Answer: Option A

A. 1.2C

Explanation

Q = CV

= 600 x 10-6 x 200 = 1.2C

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