A. CH
B. CH2
C. C2H3
D. C2H5
Correct Answer: Option C
C. C2H3
Explanation
element: C | H
Atomic Mass: 12.011 | 1.008
mass in 100 g of compound 88.9 | 11.100
we calculate the number of moles by dividing the mass by the atomic mass
# moles in 100 g : 7.40155 | 11.01190
molar ratio 7.40155 : 11.01190
smallest No : 7.4015
divide by the smallest No. : 1.000 : 1.488
Multiply by 2 : 2.000 | 2.976
empirical formula is C2H3
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![The empirical formula of a compound containing 0.067mol Cu and 0.066mol O is [Cu = 63.5, O = 16]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "The empirical formula of a compound containing 0.067mol Cu and 0.066mol O is [Cu = 63.5, O = 16]")