A. 5s
B. 20s
C. 40s
D. 60s
Correct Answer:
Option C – 40s
Explanation
Relative molecular mass of CH4 = 12 X 1 + 4 = 16
Relative molecular mass of SO2 = 32 + 10 X 2 = 64
tSO2/tCH4 = √MSO2/MCH4
t/20 = √64/16 = √4
t/20 = 2
∴ t = 20 X 2 = 40sec
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![A given volume of oxygen diffused through a porous partition in 8 seconds. How long would it take the same volume of carbon (IV) oxide to diffuse under the same condition? [C = 12.0, O = 16.0]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A given volume of oxygen diffused through a porous partition in 8 seconds. How long would it take the same volume of carbon (IV) oxide to diffuse under the same condition? [C = 12.0, O = 16.0]")
