A. 0.89 mol
B. 1.90 mol
C. 3.80 mol
D. 5.70 mol
Correct Answer:
Option A – 0.89 mol
A given amount of gas occupies 10.0dm³ at 4atm and 273°C. The number of moles of the gas present is [Molar volume of gas at s.t.p = 22.4dm³]
![Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "Calculate the mass of chlorine gas which occupies a volume of 1.12 dm³ a volume of 1.12 dm³ at s.t.p [Cl = 35.5, 1 mole of gas occupies 22.4 dm³ at s. t. p ]")
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