A. 0.0ms−1
B. 5.6ms−1
C. 10.6ms−1
D. 15.0ms−1
Correct Answer: Option C
C. 10.6ms−1
Explanation
The horizontal component of velocity, Vx, is unaffected by the acceleration of free fall and remains constant.
Vx=Ux=Ucosθ
= 15×cos45=15×0.7071
≊10.6ms−1
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![A body of mass 2kg is released from rest on a plane inclined at an angle of 60º to the horizontal. Calculate the acceleration of the body down the plane.[g = 10ms‾²]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png "A body of mass 2kg is released from rest on a plane inclined at an angle of 60º to the horizontal. Calculate the acceleration of the body down the plane.[g = 10ms‾²]")
