A chemical cell of internal resistance 1Ω supplies electric current to an external resistor of resistance 3Ω. Calculate the efficiency of the cell. by Sunday | May 21 | Physics WAEC | 0 comments A. 75% B. 50% C. 33% D. 25% Correct Answer: Option A A. 75% Explanation R = r1+ R = 1+3 = 4Ω ¾×100 = 75% Users Also Read These:A cell of e.m.f. 1.5V is connected in series with a…A cell of e.m.f. 1.5V and internal resistance of…A cell of emf 1.5V is connected in series with a 1Ω…A cell of internal resistance r supplies current to…A cell whose internal resistance is 0.55Ω delivers a…