A cell of e.m.f. 1.5 V and internal resistance of 2.59 is connected in series with an ammeter of resistance 0.59 and a resistor of resistance 7.09. Calculate the current in the circuit.

A. 0.15 A
B. 0.20 A
C. 0.60A
D. 3.00A
E. 6.67A.

Correct Answer:

Option A – 0.15 A

Explanation

I = E/R + r
=
1.5/2.5 + 0.5 + 7
= 0.15