A. 4.0 x 102N
B. 2.0 x 103N
C. 4.0 x 103N
D. 4.0 x 104N
Correct Answer:
Option C = 4.0 x 103N
Explanation
Work done = kinetic energy of the stone
½Fe= ½mv²
Given m = 500g = 0.5kg; v = 40m/s ; e = 20cm = 0.2m
F=mv²/e
= 0.5×(40)²/0.2
= 4.0 × 103 N

![Two identical charges situated 20cm apart in vacuum repel each other with a force of 1.0N. Calculate the value of each other with a force of 1.0N. Calculate the value of each charge. [(14 πεo)‾¹ = 9 x 10^9 Nm²C‾²] Two identical charges situated 20cm apart in vacuum repel each other with a force of 1.0N. Calculate the value of each other with a force of 1.0N. Calculate the value of each charge. [(14 πεo)‾¹ = 9 x 10^9 Nm²C‾²]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png)