A. 3 J
B. 4 J
C. 5 J
D. 6 J
Correct Answer:
Option A – 3J
Explanation
Effective component of the force along the horizontal = F cos 60o
Work done by this force : 60
F cos 60 x X
= 2 x 0.5 x 3
= 3J
A. 3 J
B. 4 J
C. 5 J
D. 6 J
Correct Answer:
Option A – 3J
Explanation
Effective component of the force along the horizontal = F cos 60o
Work done by this force : 60
F cos 60 x X
= 2 x 0.5 x 3
= 3J
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