A. 100N
B. 620N
C. 50N
D. 310N
Correct Answer:
Option A – 100N
Explanation
For anybody falling through a viscous liquid, at its terminal velocity. the resultant force acting on its is zero. from the equation: Mg – v – u = 0. where v = viscous drag
U = upthrust Mg = weight of the body.
∴ 36 x 10 – 260 – U = 0
∴ U = 360 – 260 = 100N
Upthrust on the body = 100N.

![A body of volume 0.046m³ is immersed in a liquid of density 980kgm‾³3 with 3/4 of its volume submerged. Calculate the upthrust on the body. [g = 10ms‾²] A body of volume 0.046m³ is immersed in a liquid of density 980kgm‾³3 with 3/4 of its volume submerged. Calculate the upthrust on the body. [g = 10ms‾²]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png)