A body of mass 20g projected vertically upwards in vacuum returns to the point of projection after 1.2s. [g = 10ms-2]. Determine the potential energy of the body at the maximum height of its motion.

by | Jan 26 | Physics WAEC | 0 comments

A. 0.36J
B. 0.72J
C. 360.00J
D. 720.00J

Correct Answer: Option A

Explanation

P.E at max = K.E on projection

= ½mv² = ½×0.02×6² = 0.36J

Users Also Read These:

Copyright warnings! Do not copy.