A. 400 J kg-1K-1
B. 500 J kg-1K-1
C. 390 J kg-1K-1
D. 130 J kg-1K-1
Correct Answer:
Option B – 500 J kg-1K-1
Explanation
Heat supplied by the heater in 10 mins
= power x time
= 50 x (10 x 60)
= 30000 J
This heat is equal = MCΔt
= 5 x c x 12
= 60cJ
= 60C = 30,000
C = 30,000/60
C = 500 J kg-1K-1

![Ice of mass 10g at 5ºC was completely converted to water at 0ºC, calculate the quantity of heat used. [specific heat capacity of ice = 2.1 Jg-1K-1, specific latent heat of fusion of ice = 336 Jg‾¹] Ice of mass 10g at 5ºC was completely converted to water at 0ºC, calculate the quantity of heat used. [specific heat capacity of ice = 2.1 Jg-1K-1, specific latent heat of fusion of ice = 336 Jg‾¹]](https://erudites.ng/wp-content/plugins/contextual-related-posts/default.png)